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Calculate 3 Phase Current from kW Power

3-Phase Current Formula:

\[ I = \frac{kW \times 1000}{\sqrt{3} \times V \times PF} \]

kW
V (line-to-line)
(0 to 1)

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1. What is 3-Phase Current Calculation?

The 3-phase current calculation determines the current flowing in each phase of a three-phase electrical system based on the power (kW), voltage, and power factor. This is essential for electrical system design, circuit protection, and equipment selection.

2. How Does the Calculator Work?

The calculator uses the 3-phase current formula:

\[ I = \frac{kW \times 1000}{\sqrt{3} \times V \times PF} \]

Where:

Explanation: The formula converts kW to watts (×1000), accounts for the 3-phase system configuration (√3), and adjusts for the power factor which represents the phase difference between voltage and current.

3. Importance of Current Calculation

Details: Accurate current calculation is crucial for selecting proper wire sizes, circuit breakers, and other protective devices to ensure safe and efficient operation of electrical systems.

4. Using the Calculator

Tips: Enter power in kW, line-to-line voltage in volts, and power factor (typically 0.8-0.95 for most industrial loads). All values must be positive (power factor between 0 and 1).

5. Frequently Asked Questions (FAQ)

Q1: What's the difference between line-to-line and line-to-neutral voltage?
A: In 3-phase systems, line-to-line voltage is between two phases, while line-to-neutral is between one phase and neutral. For balanced systems, line-to-line = √3 × line-to-neutral.

Q2: Why is power factor important?
A: Power factor affects the actual current needed to deliver a certain amount of power. Lower PF means higher current for the same real power.

Q3: What's a typical power factor value?
A: Motors typically have 0.8-0.9 PF, fluorescent lights 0.5-0.9, and resistive loads 1.0. Industrial plants often aim for ≥0.95.

Q4: How does voltage affect current?
A: For the same power, higher voltage means lower current, which reduces conductor size requirements and power losses.

Q5: Can this be used for single-phase systems?
A: No, for single-phase use \( I = \frac{kW \times 1000}{V \times PF} \) (without the √3 factor).

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